Base | Representation |
---|---|
bin | 110001010111010110… |
… | …000111111101111111 |
3 | 12001211000022021011200 |
4 | 301113112013331333 |
5 | 1332023241301101 |
6 | 40203345350543 |
7 | 3554341165011 |
oct | 612726077577 |
9 | 161730267150 |
10 | 53005025151 |
11 | 2052aa55a11 |
12 | a333338453 |
13 | 4cc94c3610 |
14 | 27cb8841b1 |
15 | 15a35cc986 |
hex | c57587f7f |
53005025151 has 24 divisors (see below), whose sum is σ = 85112017536. Its totient is φ = 31566265920.
The previous prime is 53005025083. The next prime is 53005025159. The reversal of 53005025151 is 15152050035.
53005025151 is a `hidden beast` number, since 5 + 3 + 0 + 0 + 502 + 5 + 151 = 666.
It is not a de Polignac number, because 53005025151 - 27 = 53005025023 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53005025159) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7303380 + ... + 7310633.
It is an arithmetic number, because the mean of its divisors is an integer number (3546334064).
Almost surely, 253005025151 is an apocalyptic number.
53005025151 is a deficient number, since it is larger than the sum of its proper divisors (32106992385).
53005025151 is a wasteful number, since it uses less digits than its factorization.
53005025151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14614063 (or 14614060 counting only the distinct ones).
The product of its (nonzero) digits is 3750, while the sum is 27.
Adding to 53005025151 its reverse (15152050035), we get a palindrome (68157075186).
It can be divided in two parts, 5300502 and 5151, that added together give a triangular number (5305653 = T3257).
The spelling of 53005025151 in words is "fifty-three billion, five million, twenty-five thousand, one hundred fifty-one".
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