Base | Representation |
---|---|
bin | 111100010001000000100011… |
… | …0111100111000010110111011 |
3 | 2120111221101002211002012100121 |
4 | 1320202001012330320112323 |
5 | 1023440202410334443412 |
6 | 5115234021433514111 |
7 | 216441460211310241 |
oct | 17042010674702673 |
9 | 2514841084065317 |
10 | 530103233906107 |
11 | 1439a85788604a4 |
12 | 4b555684572937 |
13 | 199a369c5c3084 |
14 | 94c91c215a791 |
15 | 41443057ab107 |
hex | 1e22046f385bb |
530103233906107 has 2 divisors, whose sum is σ = 530103233906108. Its totient is φ = 530103233906106.
The previous prime is 530103233906101. The next prime is 530103233906111. The reversal of 530103233906107 is 701609332301035.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530103233906107 is a prime.
It is not a weakly prime, because it can be changed into another prime (530103233906101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265051616953053 + 265051616953054.
It is an arithmetic number, because the mean of its divisors is an integer number (265051616953054).
Almost surely, 2530103233906107 is an apocalyptic number.
530103233906107 is a deficient number, since it is larger than the sum of its proper divisors (1).
530103233906107 is an equidigital number, since it uses as much as digits as its factorization.
530103233906107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 306180, while the sum is 43.
The spelling of 530103233906107 in words is "five hundred thirty trillion, one hundred three billion, two hundred thirty-three million, nine hundred six thousand, one hundred seven".
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