Base | Representation |
---|---|
bin | 11000000110110011011011… |
… | …11010000101101001010111 |
3 | 20221200201221001201201120112 |
4 | 30003121231322011221113 |
5 | 23422010124024430010 |
6 | 304424335355153235 |
7 | 14110604255032562 |
oct | 1403315572055127 |
9 | 227621831651515 |
10 | 53010330311255 |
11 | 15988611536589 |
12 | 5b4191044581b |
13 | 2376b114c1995 |
14 | d139dc4874d9 |
15 | 61ddc125ba05 |
hex | 30366de85a57 |
53010330311255 has 4 divisors (see below), whose sum is σ = 63612396373512. Its totient is φ = 42408264249000.
The previous prime is 53010330311227. The next prime is 53010330311273. The reversal of 53010330311255 is 55211303301035.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 53010330311255 - 220 = 53010329262679 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5301033031121 + ... + 5301033031130.
It is an arithmetic number, because the mean of its divisors is an integer number (15903099093378).
Almost surely, 253010330311255 is an apocalyptic number.
53010330311255 is a deficient number, since it is larger than the sum of its proper divisors (10602066062257).
53010330311255 is a wasteful number, since it uses less digits than its factorization.
53010330311255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10602066062256.
The product of its (nonzero) digits is 20250, while the sum is 32.
The spelling of 53010330311255 in words is "fifty-three trillion, ten billion, three hundred thirty million, three hundred eleven thousand, two hundred fifty-five".
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