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530103303112553 is a prime number
BaseRepresentation
bin111100010001000000100101…
…1000100111000011101101001
32120111221101021122022020202022
41320202001023010320131221
51023440203031044100203
65115234032345114225
7216441462011460302
oct17042011304703551
92514841248266668
10530103303112553
111439a860392a305
124b5556a3788975
13199a36b0a44631
1494c91cb4137a9
15414430b8cba38
hex1e2204b138769

530103303112553 has 2 divisors, whose sum is σ = 530103303112554. Its totient is φ = 530103303112552.

The previous prime is 530103303112501. The next prime is 530103303112571. The reversal of 530103303112553 is 355211303301035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 523788998554969 + 6314304557584 = 22886437^2 + 2512828^2 .

It is a cyclic number.

It is not a de Polignac number, because 530103303112553 - 232 = 530099008145257 is a prime.

It is not a weakly prime, because it can be changed into another prime (530102303112553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265051651556276 + 265051651556277.

It is an arithmetic number, because the mean of its divisors is an integer number (265051651556277).

Almost surely, 2530103303112553 is an apocalyptic number.

It is an amenable number.

530103303112553 is a deficient number, since it is larger than the sum of its proper divisors (1).

530103303112553 is an equidigital number, since it uses as much as digits as its factorization.

530103303112553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60750, while the sum is 35.

Adding to 530103303112553 its reverse (355211303301035), we get a palindrome (885314606413588).

The spelling of 530103303112553 in words is "five hundred thirty trillion, one hundred three billion, three hundred three million, one hundred twelve thousand, five hundred fifty-three".