Base | Representation |
---|---|
bin | 11000000110110011100101… |
… | …01111111101101010000001 |
3 | 20221200202010201120201210221 |
4 | 30003121302233331222001 |
5 | 23422010310323340134 |
6 | 304424351420223041 |
7 | 14110606262346403 |
oct | 1403316257755201 |
9 | 227622121521727 |
10 | 53010411543169 |
11 | 159886533792a3 |
12 | 5b4193369aa81 |
13 | 2376b252939c2 |
14 | d13a09190b73 |
15 | 61ddc84555b4 |
hex | 303672bfda81 |
53010411543169 has 2 divisors, whose sum is σ = 53010411543170. Its totient is φ = 53010411543168.
The previous prime is 53010411543157. The next prime is 53010411543223. The reversal of 53010411543169 is 96134511401035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52896310810225 + 114100732944 = 7272985^2 + 337788^2 .
It is a cyclic number.
It is not a de Polignac number, because 53010411543169 - 25 = 53010411543137 is a prime.
It is a super-2 number, since 2×530104115431692 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53010411543139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26505205771584 + 26505205771585.
It is an arithmetic number, because the mean of its divisors is an integer number (26505205771585).
Almost surely, 253010411543169 is an apocalyptic number.
It is an amenable number.
53010411543169 is a deficient number, since it is larger than the sum of its proper divisors (1).
53010411543169 is an equidigital number, since it uses as much as digits as its factorization.
53010411543169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 194400, while the sum is 43.
The spelling of 53010411543169 in words is "fifty-three trillion, ten billion, four hundred eleven million, five hundred forty-three thousand, one hundred sixty-nine".
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