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53011054105 = 510602210821
BaseRepresentation
bin110001010111101101…
…000111111000011001
312001211102122120100021
4301113231013320121
51332031312212410
640204122510441
73554443345102
oct612755077031
9161742576307
1053011054105
11205333a3619
12a335365421
134cca824849
1427cc5b33a9
1515a3dbdeda
hexc57b47e19

53011054105 has 4 divisors (see below), whose sum is σ = 63613264932. Its totient is φ = 42408843280.

The previous prime is 53011054091. The next prime is 53011054111. The reversal of 53011054105 is 50145011035.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 14811133401 + 38199920704 = 121701^2 + 195448^2 .

It is a de Polignac number, because none of the positive numbers 2k-53011054105 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 53011054105.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5301105406 + ... + 5301105415.

It is an arithmetic number, because the mean of its divisors is an integer number (15903316233).

Almost surely, 253011054105 is an apocalyptic number.

It is an amenable number.

53011054105 is a deficient number, since it is larger than the sum of its proper divisors (10602210827).

53011054105 is a wasteful number, since it uses less digits than its factorization.

53011054105 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10602210826.

The product of its (nonzero) digits is 1500, while the sum is 25.

The spelling of 53011054105 in words is "fifty-three billion, eleven million, fifty-four thousand, one hundred five".

Divisors: 1 5 10602210821 53011054105