Base | Representation |
---|---|
bin | 110001010111101101… |
… | …011001000010110010 |
3 | 12001211102210010202212 |
4 | 301113231121002302 |
5 | 1332031321440102 |
6 | 40204124212122 |
7 | 3554444060045 |
oct | 612755310262 |
9 | 161742703685 |
10 | 53011124402 |
11 | 20533441415 |
12 | a33539a042 |
13 | 4cca84a842 |
14 | 27cc5d0c5c |
15 | 15a3dd4c52 |
hex | c57b590b2 |
53011124402 has 4 divisors (see below), whose sum is σ = 79516686606. Its totient is φ = 26505562200.
The previous prime is 53011124357. The next prime is 53011124443. The reversal of 53011124402 is 20442111035.
53011124402 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20442111035 = 5 ⋅4088422207.
It can be written as a sum of positive squares in only one way, i.e., 47066868601 + 5944255801 = 216949^2 + 77099^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13252781099 + ... + 13252781102.
Almost surely, 253011124402 is an apocalyptic number.
53011124402 is a deficient number, since it is larger than the sum of its proper divisors (26505562204).
53011124402 is a wasteful number, since it uses less digits than its factorization.
53011124402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26505562203.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 53011124402 its reverse (20442111035), we get a palindrome (73453235437).
The spelling of 53011124402 in words is "fifty-three billion, eleven million, one hundred twenty-four thousand, four hundred two".
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