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53011124403 = 329609323269
BaseRepresentation
bin110001010111101101…
…011001000010110011
312001211102210010202220
4301113231121002303
51332031321440103
640204124212123
73554444060046
oct612755310263
9161742703686
1053011124403
1120533441416
12a33539a043
134cca84a843
1427cc5d0c5d
1515a3dd4c53
hexc57b590b3

53011124403 has 8 divisors (see below), whose sum is σ = 73118792400. Its totient is φ = 34122103008.

The previous prime is 53011124357. The next prime is 53011124443. The reversal of 53011124403 is 30442111035.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 53011124403 - 28 = 53011124147 is a prime.

It is not an unprimeable number, because it can be changed into a prime (53011124443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 304661548 + ... + 304661721.

It is an arithmetic number, because the mean of its divisors is an integer number (9139849050).

Almost surely, 253011124403 is an apocalyptic number.

53011124403 is a deficient number, since it is larger than the sum of its proper divisors (20107667997).

53011124403 is a wasteful number, since it uses less digits than its factorization.

53011124403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 609323301.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 53011124403 its reverse (30442111035), we get a palindrome (83453235438).

The spelling of 53011124403 in words is "fifty-three billion, eleven million, one hundred twenty-four thousand, four hundred three".

Divisors: 1 3 29 87 609323269 1827969807 17670374801 53011124403