Base | Representation |
---|---|
bin | 111100010001000101100101… |
… | …1000110101011100010100110 |
3 | 2120111222101222222112120010000 |
4 | 1320202023023012223202212 |
5 | 1023440342023444032100 |
6 | 5115243010051242130 |
7 | 216442322056152003 |
oct | 17042131306534246 |
9 | 2514871888476100 |
10 | 530114041002150 |
11 | 143a02114112730 |
12 | 4b55779b8a9346 |
13 | 199a4702579267 |
14 | 94c99295748aa |
15 | 4144739443900 |
hex | 1e222cb1ab8a6 |
530114041002150 has 480 divisors, whose sum is σ = 1664520827286240. Its totient is φ = 123969263616000.
The previous prime is 530114041002089. The next prime is 530114041002179. The reversal of 530114041002150 is 51200140411035.
530114041002150 is a `hidden beast` number, since 5 + 3 + 0 + 1 + 1 + 404 + 100 + 2 + 150 = 666.
It is a super-3 number, since 3×5301140410021503 (a number of 45 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 160932462 + ... + 164193438.
It is an arithmetic number, because the mean of its divisors is an integer number (3467751723513).
Almost surely, 2530114041002150 is an apocalyptic number.
530114041002150 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 530114041002150, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (832260413643120).
530114041002150 is an abundant number, since it is smaller than the sum of its proper divisors (1134406786284090).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530114041002150 is a wasteful number, since it uses less digits than its factorization.
530114041002150 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3261142 (or 3261128 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
Adding to 530114041002150 its reverse (51200140411035), we get a palindrome (581314181413185).
The spelling of 530114041002150 in words is "five hundred thirty trillion, one hundred fourteen billion, forty-one million, two thousand, one hundred fifty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •