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53013165300521 is a prime number
BaseRepresentation
bin11000000110111000101101…
…11000101101101100101001
320221201000020122021002201222
430003130112320231230221
523422031430304104041
6304425524550551425
714111034441036446
oct1403342670555451
9227630218232658
1053013165300521
1115989836841a18
125b42381968575
13237717394cb1a
14d13bcabb89cd
1561deda0a874b
hex303716e2db29

53013165300521 has 2 divisors, whose sum is σ = 53013165300522. Its totient is φ = 53013165300520.

The previous prime is 53013165300503. The next prime is 53013165300527. The reversal of 53013165300521 is 12500356131035.

53013165300521 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41580895305625 + 11432269994896 = 6448325^2 + 3381164^2 .

It is a cyclic number.

It is not a de Polignac number, because 53013165300521 - 218 = 53013165038377 is a prime.

It is not a weakly prime, because it can be changed into another prime (53013165300527) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26506582650260 + 26506582650261.

It is an arithmetic number, because the mean of its divisors is an integer number (26506582650261).

Almost surely, 253013165300521 is an apocalyptic number.

It is an amenable number.

53013165300521 is a deficient number, since it is larger than the sum of its proper divisors (1).

53013165300521 is an equidigital number, since it uses as much as digits as its factorization.

53013165300521 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40500, while the sum is 35.

The spelling of 53013165300521 in words is "fifty-three trillion, thirteen billion, one hundred sixty-five million, three hundred thousand, five hundred twenty-one".