Base | Representation |
---|---|
bin | 110001010111111001… |
… | …111001000110101111 |
3 | 12001211122221122001012 |
4 | 301113321321012233 |
5 | 1332033141321310 |
6 | 40204322335435 |
7 | 3554513656121 |
oct | 612771710657 |
9 | 161748848035 |
10 | 53014401455 |
11 | 2053527a524 |
12 | a3364ba57b |
13 | 4ccb427322 |
14 | 27ccc05211 |
15 | 15a4330c05 |
hex | c57e791af |
53014401455 has 4 divisors (see below), whose sum is σ = 63617281752. Its totient is φ = 42411521160.
The previous prime is 53014401439. The next prime is 53014401463. The reversal of 53014401455 is 55410441035.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 55410441035 = 5 ⋅11082088207.
It is not a de Polignac number, because 53014401455 - 24 = 53014401439 is a prime.
It is a super-2 number, since 2×530144014552 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5301440141 + ... + 5301440150.
It is an arithmetic number, because the mean of its divisors is an integer number (15904320438).
Almost surely, 253014401455 is an apocalyptic number.
53014401455 is a deficient number, since it is larger than the sum of its proper divisors (10602880297).
53014401455 is a wasteful number, since it uses less digits than its factorization.
53014401455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10602880296.
The product of its (nonzero) digits is 24000, while the sum is 32.
The spelling of 53014401455 in words is "fifty-three billion, fourteen million, four hundred one thousand, four hundred fifty-five".
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