Base | Representation |
---|---|
bin | 110001010111111001… |
… | …111001000111110011 |
3 | 12001211122221122010201 |
4 | 301113321321013303 |
5 | 1332033141322043 |
6 | 40204322340031 |
7 | 3554513656246 |
oct | 612771710763 |
9 | 161748848121 |
10 | 53014401523 |
11 | 2053527a586 |
12 | a3364ba617 |
13 | 4ccb427375 |
14 | 27ccc0525d |
15 | 15a4330c4d |
hex | c57e791f3 |
53014401523 has 2 divisors, whose sum is σ = 53014401524. Its totient is φ = 53014401522.
The previous prime is 53014401499. The next prime is 53014401541. The reversal of 53014401523 is 32510441035.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53014401523 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53014401491 and 53014401500.
It is not a weakly prime, because it can be changed into another prime (53014401593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507200761 + 26507200762.
It is an arithmetic number, because the mean of its divisors is an integer number (26507200762).
Almost surely, 253014401523 is an apocalyptic number.
53014401523 is a deficient number, since it is larger than the sum of its proper divisors (1).
53014401523 is an equidigital number, since it uses as much as digits as its factorization.
53014401523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 53014401523 its reverse (32510441035), we get a palindrome (85524842558).
The spelling of 53014401523 in words is "fifty-three billion, fourteen million, four hundred one thousand, five hundred twenty-three".
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