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53014603 is a prime number
BaseRepresentation
bin1100101000111…
…1000001001011
310200202102100211
43022033001023
5102032431403
65132141551
71212421345
oct312170113
9120672324
1053014603
1127a1a724
12159078b7
13aca25b5
147080295
1549c306d
hex328f04b

53014603 has 2 divisors, whose sum is σ = 53014604. Its totient is φ = 53014602.

The previous prime is 53014589. The next prime is 53014613. The reversal of 53014603 is 30641035.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53014603 - 213 = 53006411 is a prime.

It is not a weakly prime, because it can be changed into another prime (53014613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507301 + 26507302.

It is an arithmetic number, because the mean of its divisors is an integer number (26507302).

Almost surely, 253014603 is an apocalyptic number.

53014603 is a deficient number, since it is larger than the sum of its proper divisors (1).

53014603 is an equidigital number, since it uses as much as digits as its factorization.

53014603 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 22.

The square root of 53014603 is about 7281.1127583632. The cubic root of 53014603 is about 375.6630710220.

Adding to 53014603 its reverse (30641035), we get a palindrome (83655638).

The spelling of 53014603 in words is "fifty-three million, fourteen thousand, six hundred three".