Base | Representation |
---|---|
bin | 11111100110010… |
… | …110001101000010 |
3 | 1100221120012202021 |
4 | 133212112031002 |
5 | 2041204133424 |
6 | 124334512054 |
7 | 16065111331 |
oct | 3746261502 |
9 | 1327505667 |
10 | 530146114 |
11 | 252287693 |
12 | 12966562a |
13 | 85aab734 |
14 | 505a1d18 |
15 | 318204e4 |
hex | 1f996342 |
530146114 has 4 divisors (see below), whose sum is σ = 795219174. Its totient is φ = 265073056.
The previous prime is 530146091. The next prime is 530146163. The reversal of 530146114 is 411641035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 459030625 + 71115489 = 21425^2 + 8433^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132536527 + ... + 132536530.
Almost surely, 2530146114 is an apocalyptic number.
530146114 is a deficient number, since it is larger than the sum of its proper divisors (265073060).
530146114 is a wasteful number, since it uses less digits than its factorization.
530146114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 265073059.
The product of its (nonzero) digits is 1440, while the sum is 25.
The square root of 530146114 is about 23024.9020410511. The cubic root of 530146114 is about 809.3415947195.
Adding to 530146114 its reverse (411641035), we get a palindrome (941787149).
It can be divided in two parts, 5301 and 46114, that added together give a palindrome (51415).
The spelling of 530146114 in words is "five hundred thirty million, one hundred forty-six thousand, one hundred fourteen".
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