Base | Representation |
---|---|
bin | 1001110111111111… |
… | …00110110000001011 |
3 | 111200110200221110221 |
4 | 10323333212300023 |
5 | 41324140344333 |
6 | 2234021250511 |
7 | 245242660006 |
oct | 47377466013 |
9 | 14613627427 |
10 | 5301496843 |
11 | 2280614055 |
12 | 103b563a37 |
13 | 666461aa6 |
14 | 38414453d |
15 | 21065dd2d |
hex | 13bfe6c0b |
5301496843 has 2 divisors, whose sum is σ = 5301496844. Its totient is φ = 5301496842.
The previous prime is 5301496769. The next prime is 5301496847. The reversal of 5301496843 is 3486941035.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5301496843 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5301496843.
It is not a weakly prime, because it can be changed into another prime (5301496847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2650748421 + 2650748422.
It is an arithmetic number, because the mean of its divisors is an integer number (2650748422).
Almost surely, 25301496843 is an apocalyptic number.
5301496843 is a deficient number, since it is larger than the sum of its proper divisors (1).
5301496843 is an equidigital number, since it uses as much as digits as its factorization.
5301496843 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 43.
The square root of 5301496843 is about 72811.3785269857. The cubic root of 5301496843 is about 1743.6775220313.
The spelling of 5301496843 in words is "five billion, three hundred one million, four hundred ninety-six thousand, eight hundred forty-three".
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