Base | Representation |
---|---|
bin | 110001011000000000… |
… | …111101011010100001 |
3 | 12001211210102202102011 |
4 | 301120000331122201 |
5 | 1332034130112423 |
6 | 40204430152521 |
7 | 3554535503344 |
oct | 613000753241 |
9 | 161753382364 |
10 | 53016254113 |
11 | 20536325449 |
12 | a337052741 |
13 | 4ccb925684 |
14 | 27cd16845b |
15 | 15a4599b0d |
hex | c5803d6a1 |
53016254113 has 2 divisors, whose sum is σ = 53016254114. Its totient is φ = 53016254112.
The previous prime is 53016254089. The next prime is 53016254117. The reversal of 53016254113 is 31145261035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28175972449 + 24840281664 = 167857^2 + 157608^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53016254113 is a prime.
It is not a weakly prime, because it can be changed into another prime (53016254117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26508127056 + 26508127057.
It is an arithmetic number, because the mean of its divisors is an integer number (26508127057).
Almost surely, 253016254113 is an apocalyptic number.
It is an amenable number.
53016254113 is a deficient number, since it is larger than the sum of its proper divisors (1).
53016254113 is an equidigital number, since it uses as much as digits as its factorization.
53016254113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 31.
The spelling of 53016254113 in words is "fifty-three billion, sixteen million, two hundred fifty-four thousand, one hundred thirteen".
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