Base | Representation |
---|---|
bin | 110001011000001111… |
… | …011010101101101101 |
3 | 12001212001120022100120 |
4 | 301120033122231231 |
5 | 1332041112403031 |
6 | 40205043315153 |
7 | 3554612640111 |
oct | 613017325555 |
9 | 161761508316 |
10 | 53020044141 |
11 | 205384839a9 |
12 | a33837bab9 |
13 | 4ccc6517ac |
14 | 27cd873741 |
15 | 15a4a97a96 |
hex | c583dab6d |
53020044141 has 16 divisors (see below), whose sum is σ = 74486216640. Its totient is φ = 33453889920.
The previous prime is 53020044139. The next prime is 53020044151. The reversal of 53020044141 is 14144002035.
It is not a de Polignac number, because 53020044141 - 21 = 53020044139 is a prime.
It is a super-2 number, since 2×530200441412 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53020044151) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 391350 + ... + 509111.
It is an arithmetic number, because the mean of its divisors is an integer number (4655388540).
Almost surely, 253020044141 is an apocalyptic number.
It is an amenable number.
53020044141 is a deficient number, since it is larger than the sum of its proper divisors (21466172499).
53020044141 is a wasteful number, since it uses less digits than its factorization.
53020044141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 901516.
The product of its (nonzero) digits is 1920, while the sum is 24.
Adding to 53020044141 its reverse (14144002035), we get a palindrome (67164046176).
The spelling of 53020044141 in words is "fifty-three billion, twenty million, forty-four thousand, one hundred forty-one".
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