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5302121335 = 571091389809
BaseRepresentation
bin1001111000000011…
…11111001101110111
3111200111212200010021
410330001333031313
541324320340320
62234042510011
7245251200460
oct47401771567
914614780107
105302121335
112280a00265
12103b805307
13666620104
14384267d67
15210733daa
hex13c07f377

5302121335 has 16 divisors (see below), whose sum is σ = 7338196800. Its totient is φ = 3602382336.

The previous prime is 5302121329. The next prime is 5302121339. The reversal of 5302121335 is 5331212035.

It is not a de Polignac number, because 5302121335 - 25 = 5302121303 is a prime.

It is a super-2 number, since 2×53021213352 = 56224981302124364450, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5302121339) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 691090 + ... + 698719.

It is an arithmetic number, because the mean of its divisors is an integer number (458637300).

Almost surely, 25302121335 is an apocalyptic number.

5302121335 is a deficient number, since it is larger than the sum of its proper divisors (2036075465).

5302121335 is a wasteful number, since it uses less digits than its factorization.

5302121335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1389930.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 5302121335 is about 72815.6668238368. Note that the first 3 decimals coincide. The cubic root of 5302121335 is about 1743.7459850800.

The spelling of 5302121335 in words is "five billion, three hundred two million, one hundred twenty-one thousand, three hundred thirty-five".

Divisors: 1 5 7 35 109 545 763 3815 1389809 6949045 9728663 48643315 151489181 757445905 1060424267 5302121335