Base | Representation |
---|---|
bin | 1111011011100110010… |
… | …10100000101111101001 |
3 | 1212200120110111212102122 |
4 | 13231303022200233221 |
5 | 32141334024102214 |
6 | 1043324311041025 |
7 | 53210114045342 |
oct | 7556312405751 |
9 | 1780513455378 |
10 | 530213112809 |
11 | 194953530316 |
12 | 86913370175 |
13 | 3acca70b813 |
14 | 1b93baa50c9 |
15 | dbd330688e |
hex | 7b732a0be9 |
530213112809 has 2 divisors, whose sum is σ = 530213112810. Its totient is φ = 530213112808.
The previous prime is 530213112733. The next prime is 530213112907. The reversal of 530213112809 is 908211312035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 525733755625 + 4479357184 = 725075^2 + 66928^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530213112809 is a prime.
It is a super-2 number, since 2×5302131128092 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (530213012809) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265106556404 + 265106556405.
It is an arithmetic number, because the mean of its divisors is an integer number (265106556405).
Almost surely, 2530213112809 is an apocalyptic number.
It is an amenable number.
530213112809 is a deficient number, since it is larger than the sum of its proper divisors (1).
530213112809 is an equidigital number, since it uses as much as digits as its factorization.
530213112809 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 35.
The spelling of 530213112809 in words is "five hundred thirty billion, two hundred thirteen million, one hundred twelve thousand, eight hundred nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •