Base | Representation |
---|---|
bin | 110001011000010100… |
… | …101011100001010011 |
3 | 12001212011011101202022 |
4 | 301120110223201103 |
5 | 1332041441024244 |
6 | 40205133042055 |
7 | 3554630444126 |
oct | 613024534123 |
9 | 161764141668 |
10 | 53021423699 |
11 | 20539236432 |
12 | a33892632b |
13 | 4ccca156ba |
14 | 27cdb123bd |
15 | 15a4c6b6ee |
hex | c5852b853 |
53021423699 has 2 divisors, whose sum is σ = 53021423700. Its totient is φ = 53021423698.
The previous prime is 53021423681. The next prime is 53021423759. The reversal of 53021423699 is 99632412035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53021423699 - 212 = 53021419603 is a prime.
It is a super-3 number, since 3×530214236993 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (53021473699) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26510711849 + 26510711850.
It is an arithmetic number, because the mean of its divisors is an integer number (26510711850).
Almost surely, 253021423699 is an apocalyptic number.
53021423699 is a deficient number, since it is larger than the sum of its proper divisors (1).
53021423699 is an equidigital number, since it uses as much as digits as its factorization.
53021423699 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 349920, while the sum is 44.
The spelling of 53021423699 in words is "fifty-three billion, twenty-one million, four hundred twenty-three thousand, six hundred ninety-nine".
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