Base | Representation |
---|---|
bin | 110001011000010100… |
… | …101101110010101000 |
3 | 12001212011011212111210 |
4 | 301120110231302220 |
5 | 1332041441324000 |
6 | 40205133153120 |
7 | 3554630513214 |
oct | 613024556250 |
9 | 161764155453 |
10 | 53021433000 |
11 | 20539242418 |
12 | a33892b7a0 |
13 | 4ccca199c3 |
14 | 27cdb15944 |
15 | 15a4c6e350 |
hex | c5852dca8 |
53021433000 has 256 divisors, whose sum is σ = 168560870400. Its totient is φ = 13873305600.
The previous prime is 53021432993. The next prime is 53021433013. The reversal of 53021433000 is 33412035.
It is a super-2 number, since 2×530214330002 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 52340494 + ... + 52341506.
It is an arithmetic number, because the mean of its divisors is an integer number (658440900).
Almost surely, 253021433000 is an apocalyptic number.
53021433000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 53021433000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (84280435200).
53021433000 is an abundant number, since it is smaller than the sum of its proper divisors (115539437400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53021433000 is a wasteful number, since it uses less digits than its factorization.
53021433000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1349 (or 1335 counting only the distinct ones).
The product of its (nonzero) digits is 1080, while the sum is 21.
Adding to 53021433000 its reverse (33412035), we get a palindrome (53054845035).
The spelling of 53021433000 in words is "fifty-three billion, twenty-one million, four hundred thirty-three thousand".
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