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53021432999 = 523101379413
BaseRepresentation
bin110001011000010100…
…101101110010100111
312001212011011212111202
4301120110231302213
51332041441323444
640205133153115
73554630513213
oct613024556247
9161764155452
1053021432999
1120539242417
12a33892b79b
134ccca199c2
1427cdb15943
1515a4c6e34e
hexc5852dca7

53021432999 has 4 divisors (see below), whose sum is σ = 53122812936. Its totient is φ = 52920053064.

The previous prime is 53021432993. The next prime is 53021433013. The reversal of 53021432999 is 99923412035.

53021432999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 99923412035 = 519984682407.

It is a cyclic number.

It is not a de Polignac number, because 53021432999 - 216 = 53021367463 is a prime.

It is a super-2 number, since 2×530214329992 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53021432993) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50689184 + ... + 50690229.

It is an arithmetic number, because the mean of its divisors is an integer number (13280703234).

Almost surely, 253021432999 is an apocalyptic number.

53021432999 is a deficient number, since it is larger than the sum of its proper divisors (101379937).

53021432999 is a wasteful number, since it uses less digits than its factorization.

53021432999 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 101379936.

The product of its (nonzero) digits is 524880, while the sum is 47.

The spelling of 53021432999 in words is "fifty-three billion, twenty-one million, four hundred thirty-two thousand, nine hundred ninety-nine".

Divisors: 1 523 101379413 53021432999