Base | Representation |
---|---|
bin | 110001011000010101… |
… | …000001000101011111 |
3 | 12001212011022212220212 |
4 | 301120111001011133 |
5 | 1332042001341111 |
6 | 40205135003035 |
7 | 3554631262505 |
oct | 613025010537 |
9 | 161764285825 |
10 | 53021512031 |
11 | 20539296834 |
12 | a33896947b |
13 | 4ccca46977 |
14 | 27cdb36675 |
15 | 15a4c8798b |
hex | c5854115f |
53021512031 has 4 divisors (see below), whose sum is σ = 53025508032. Its totient is φ = 53017516032.
The previous prime is 53021512003. The next prime is 53021512039. The reversal of 53021512031 is 13021512035.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53021512031 - 218 = 53021249887 is a prime.
It is a super-3 number, since 3×530215120313 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53021511988 and 53021512006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53021512039) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1978031 + ... + 2004656.
It is an arithmetic number, because the mean of its divisors is an integer number (13256377008).
Almost surely, 253021512031 is an apocalyptic number.
53021512031 is a deficient number, since it is larger than the sum of its proper divisors (3996001).
53021512031 is a wasteful number, since it uses less digits than its factorization.
53021512031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3996000.
The product of its (nonzero) digits is 900, while the sum is 23.
The spelling of 53021512031 in words is "fifty-three billion, twenty-one million, five hundred twelve thousand, thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •