Base | Representation |
---|---|
bin | 110001011000010101… |
… | …000001010111111011 |
3 | 12001212011022221112120 |
4 | 301120111001113323 |
5 | 1332042001410321 |
6 | 40205135012323 |
7 | 3554631266112 |
oct | 613025012773 |
9 | 161764287476 |
10 | 53021513211 |
11 | 20539297707 |
12 | a33896a0a3 |
13 | 4ccca47374 |
14 | 27cdb36c79 |
15 | 15a4c87ec6 |
hex | c585415fb |
53021513211 has 16 divisors (see below), whose sum is σ = 70963944480. Its totient is φ = 35213573120.
The previous prime is 53021513143. The next prime is 53021513213. The reversal of 53021513211 is 11231512035.
53021513211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53021513211 is a prime.
It is a super-2 number, since 2×530215132112 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (53021513213) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1100005 + ... + 1147193.
It is an arithmetic number, because the mean of its divisors is an integer number (4435246530).
Almost surely, 253021513211 is an apocalyptic number.
53021513211 is a deficient number, since it is larger than the sum of its proper divisors (17942431269).
53021513211 is a wasteful number, since it uses less digits than its factorization.
53021513211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48606.
The product of its (nonzero) digits is 900, while the sum is 24.
The spelling of 53021513211 in words is "fifty-three billion, twenty-one million, five hundred thirteen thousand, two hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •