Base | Representation |
---|---|
bin | 110001011000010111… |
… | …011101011101010101 |
3 | 12001212012112102112011 |
4 | 301120113131131111 |
5 | 1332042132340113 |
6 | 40205200424221 |
7 | 3554636601040 |
oct | 613027353525 |
9 | 161765472464 |
10 | 53022152533 |
11 | 20539693a79 |
12 | a339018071 |
13 | 4cccc0c36c |
14 | 27cdc61c57 |
15 | 15a4d6263d |
hex | c585dd755 |
53022152533 has 32 divisors (see below), whose sum is σ = 67985879040. Its totient is φ = 40254278400.
The previous prime is 53022152483. The next prime is 53022152549. The reversal of 53022152533 is 33525122035.
It is a de Polignac number, because none of the positive numbers 2k-53022152533 is a prime.
It is a super-2 number, since 2×530221525332 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53022152495 and 53022152504.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53022152033) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 263760 + ... + 419062.
It is an arithmetic number, because the mean of its divisors is an integer number (2124558720).
Almost surely, 253022152533 is an apocalyptic number.
It is an amenable number.
53022152533 is a deficient number, since it is larger than the sum of its proper divisors (14963726507).
53022152533 is a wasteful number, since it uses less digits than its factorization.
53022152533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 155497.
The product of its (nonzero) digits is 27000, while the sum is 31.
Adding to 53022152533 its reverse (33525122035), we get a palindrome (86547274568).
The spelling of 53022152533 in words is "fifty-three billion, twenty-two million, one hundred fifty-two thousand, five hundred thirty-three".
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