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53022223133513 is a prime number
BaseRepresentation
bin11000000111001001100101…
…10001100110101101001001
320221201212121220011200200222
430003210302301212231021
523422204003110233023
6304434023435435425
714111505055251014
oct1403446261465511
9227655556150628
1053022223133513
1115992664743a07
125b4408b2b5b75
132377c8839b90a
14d14409b6637b
1561e36a3aacc8
hex303932c66b49

53022223133513 has 2 divisors, whose sum is σ = 53022223133514. Its totient is φ = 53022223133512.

The previous prime is 53022223133501. The next prime is 53022223133543. The reversal of 53022223133513 is 31533132222035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26908620771904 + 26113602361609 = 5187352^2 + 5110147^2 .

It is a cyclic number.

It is not a de Polignac number, because 53022223133513 - 230 = 53021149391689 is a prime.

It is a super-3 number, since 3×530222231335133 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (53022223133543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26511111566756 + 26511111566757.

It is an arithmetic number, because the mean of its divisors is an integer number (26511111566757).

Almost surely, 253022223133513 is an apocalyptic number.

It is an amenable number.

53022223133513 is a deficient number, since it is larger than the sum of its proper divisors (1).

53022223133513 is an equidigital number, since it uses as much as digits as its factorization.

53022223133513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 97200, while the sum is 35.

Adding to 53022223133513 its reverse (31533132222035), we get a palindrome (84555355355548).

The spelling of 53022223133513 in words is "fifty-three trillion, twenty-two billion, two hundred twenty-three million, one hundred thirty-three thousand, five hundred thirteen".