53022223133535 has 8 divisors (see below), whose sum is σ = 84835557013680. Its totient is φ = 28278519004544.

The previous prime is 53022223133513. The next prime is 53022223133543. The reversal of 53022223133535 is 53533132222035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 53022223133535 - 2¹² = 53022223129439 is a prime.

It is a super-3 number, since 3×53022223133535³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 53022223133493 and 53022223133502.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1767407437770 + ... + 1767407437799.

It is an arithmetic number, because the mean of its divisors is an integer number (10604444626710).

Almost surely, 2^{53022223133535} is an apocalyptic number.

53022223133535 is a deficient number, since it is larger than the sum of its proper divisors (31813333880145).

53022223133535 is a wasteful number, since it uses less digits than its factorization.

53022223133535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3534814875577.

The product of its (nonzero) digits is 486000, while the sum is 39.

The spelling of 53022223133535 in words is "fifty-three trillion, twenty-two billion, two hundred twenty-three million, one hundred thirty-three thousand, five hundred thirty-five".