Base | Representation |
---|---|
bin | 1111011011100111100… |
… | …00010010001000100001 |
3 | 1212200121011010220220110 |
4 | 13231303300102020201 |
5 | 32141344042430213 |
6 | 1043325303201533 |
7 | 53210264155140 |
oct | 7556360221041 |
9 | 1780534126813 |
10 | 530223014433 |
11 | 194959083582 |
12 | 869167462a9 |
13 | 3accc797678 |
14 | 1b93d121757 |
15 | dbd41105c3 |
hex | 7b73c12221 |
530223014433 has 64 divisors (see below), whose sum is σ = 822649856000. Its totient is φ = 297522201600.
The previous prime is 530223014413. The next prime is 530223014507. The reversal of 530223014433 is 334410322035.
It is not a de Polignac number, because 530223014433 - 216 = 530222948897 is a prime.
It is a super-2 number, since 2×5302230144332 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 530223014433.
It is not an unprimeable number, because it can be changed into a prime (530223014413) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 312078618 + ... + 312080316.
It is an arithmetic number, because the mean of its divisors is an integer number (12853904000).
Almost surely, 2530223014433 is an apocalyptic number.
It is an amenable number.
530223014433 is a deficient number, since it is larger than the sum of its proper divisors (292426841567).
530223014433 is a wasteful number, since it uses less digits than its factorization.
530223014433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2702.
The product of its (nonzero) digits is 25920, while the sum is 30.
Adding to 530223014433 its reverse (334410322035), we get a palindrome (864633336468).
The spelling of 530223014433 in words is "five hundred thirty billion, two hundred twenty-three million, fourteen thousand, four hundred thirty-three".
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