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5302354163401 is a prime number
BaseRepresentation
bin100110100101000110011…
…1011111011011011001001
3200202220022011211001020101
41031022030323323123021
51143333210131212101
615135511243325401
71055040164513611
oct115121473733311
920686264731211
105302354163401
111764796769649
1271776b820861
132c6018850469
141448c7415a41
1592dd6900401
hex4d28cefb6c9

5302354163401 has 2 divisors, whose sum is σ = 5302354163402. Its totient is φ = 5302354163400.

The previous prime is 5302354163369. The next prime is 5302354163413. The reversal of 5302354163401 is 1043614532035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5147294625225 + 155059538176 = 2268765^2 + 393776^2 .

It is a cyclic number.

It is not a de Polignac number, because 5302354163401 - 25 = 5302354163369 is a prime.

It is a super-2 number, since 2×53023541634012 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5302354163501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651177081700 + 2651177081701.

It is an arithmetic number, because the mean of its divisors is an integer number (2651177081701).

Almost surely, 25302354163401 is an apocalyptic number.

It is an amenable number.

5302354163401 is a deficient number, since it is larger than the sum of its proper divisors (1).

5302354163401 is an equidigital number, since it uses as much as digits as its factorization.

5302354163401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 37.

Adding to 5302354163401 its reverse (1043614532035), we get a palindrome (6345968695436).

The spelling of 5302354163401 in words is "five trillion, three hundred two billion, three hundred fifty-four million, one hundred sixty-three thousand, four hundred one".