Base | Representation |
---|---|
bin | 1111011011101001110… |
… | …10110001001100010111 |
3 | 1212200122111212221101010 |
4 | 13231310322301030113 |
5 | 32141414042242221 |
6 | 1043331241503303 |
7 | 53210622140661 |
oct | 7556472611427 |
9 | 1780574787333 |
10 | 530242540311 |
11 | 1949690aa670 |
12 | 869211a1b33 |
13 | 3b003843043 |
14 | 1b941965531 |
15 | dbd5bbac76 |
hex | 7b74eb1317 |
530242540311 has 8 divisors (see below), whose sum is σ = 771261876864. Its totient is φ = 321359115320.
The previous prime is 530242540307. The next prime is 530242540313. The reversal of 530242540311 is 113045242035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530242540311 - 22 = 530242540307 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530242540313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8033977851 + ... + 8033977916.
It is an arithmetic number, because the mean of its divisors is an integer number (96407734608).
Almost surely, 2530242540311 is an apocalyptic number.
530242540311 is a deficient number, since it is larger than the sum of its proper divisors (241019336553).
530242540311 is a wasteful number, since it uses less digits than its factorization.
530242540311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16067955781.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 530242540311 its reverse (113045242035), we get a palindrome (643287782346).
The spelling of 530242540311 in words is "five hundred thirty billion, two hundred forty-two million, five hundred forty thousand, three hundred eleven".
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