Base | Representation |
---|---|
bin | 111100010010000001101111… |
… | …0001011101100111011010111 |
3 | 2120112102202101222222211111002 |
4 | 1320210003132023230323113 |
5 | 1024000001043241321120 |
6 | 5115422211245333515 |
7 | 216454544023335224 |
oct | 17044033613547327 |
9 | 2515382358884432 |
10 | 530243210104535 |
11 | 143a51978768114 |
12 | 4b57882a26729b |
13 | 199b39492704a5 |
14 | 94d1ca055094b |
15 | 4147c9937a375 |
hex | 1e240de2eced7 |
530243210104535 has 4 divisors (see below), whose sum is σ = 636291852125448. Its totient is φ = 424194568083624.
The previous prime is 530243210104471. The next prime is 530243210104549. The reversal of 530243210104535 is 535401012342035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 530243210104535 - 26 = 530243210104471 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53024321010449 + ... + 53024321010458.
It is an arithmetic number, because the mean of its divisors is an integer number (159072963031362).
Almost surely, 2530243210104535 is an apocalyptic number.
530243210104535 is a deficient number, since it is larger than the sum of its proper divisors (106048642020913).
530243210104535 is a wasteful number, since it uses less digits than its factorization.
530243210104535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 106048642020912.
The product of its (nonzero) digits is 216000, while the sum is 38.
The spelling of 530243210104535 in words is "five hundred thirty trillion, two hundred forty-three billion, two hundred ten million, one hundred four thousand, five hundred thirty-five".
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