Base | Representation |
---|---|
bin | 100110100101001000110… |
… | …1010101110111110010111 |
3 | 200202220111201011220020221 |
4 | 1031022101222232332113 |
5 | 1143333340441321124 |
6 | 15135523200535211 |
7 | 1055042150311324 |
oct | 115122152567627 |
9 | 20686451156227 |
10 | 5302433542039 |
11 | 1764827555a27 |
12 | 717792321507 |
13 | 2c602c123a7a |
14 | 1448d3b99b4b |
15 | 92ddd87ece4 |
hex | 4d291aaef97 |
5302433542039 has 8 divisors (see below), whose sum is σ = 5700264503040. Its totient is φ = 4916478132216.
The previous prime is 5302433542037. The next prime is 5302433542067. The reversal of 5302433542039 is 9302453342035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5302433542039 - 21 = 5302433542037 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5302433541986 and 5302433542004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5302433542033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2968886869 + ... + 2968888654.
It is an arithmetic number, because the mean of its divisors is an integer number (712533062880).
Almost surely, 25302433542039 is an apocalyptic number.
5302433542039 is a deficient number, since it is larger than the sum of its proper divisors (397830961001).
5302433542039 is a wasteful number, since it uses less digits than its factorization.
5302433542039 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5937775589.
The product of its (nonzero) digits is 1166400, while the sum is 43.
The spelling of 5302433542039 in words is "five trillion, three hundred two billion, four hundred thirty-three million, five hundred forty-two thousand, thirty-nine".
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