Base | Representation |
---|---|
bin | 1111011011101001111… |
… | …10001111010110111101 |
3 | 1212200122120121011122110 |
4 | 13231310332033112331 |
5 | 32141414310402201 |
6 | 1043331313204233 |
7 | 53210632651005 |
oct | 7556476172675 |
9 | 1780576534573 |
10 | 530243450301 |
11 | 194969671324 |
12 | 86921560679 |
13 | 3b003aa12b6 |
14 | 1b941b21005 |
15 | dbd5cea6d6 |
hex | 7b74f8f5bd |
530243450301 has 4 divisors (see below), whose sum is σ = 706991267072. Its totient is φ = 353495633532.
The previous prime is 530243450293. The next prime is 530243450339. The reversal of 530243450301 is 103054342035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 530243450301 - 23 = 530243450293 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530243450351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88373908381 + ... + 88373908386.
It is an arithmetic number, because the mean of its divisors is an integer number (176747816768).
Almost surely, 2530243450301 is an apocalyptic number.
It is an amenable number.
530243450301 is a deficient number, since it is larger than the sum of its proper divisors (176747816771).
530243450301 is a wasteful number, since it uses less digits than its factorization.
530243450301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 176747816770.
The product of its (nonzero) digits is 21600, while the sum is 30.
Adding to 530243450301 its reverse (103054342035), we get a palindrome (633297792336).
The spelling of 530243450301 in words is "five hundred thirty billion, two hundred forty-three million, four hundred fifty thousand, three hundred one".
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