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530246137 is a prime number
BaseRepresentation
bin11111100110101…
…110100111111001
31100221202021221211
4133212232213321
52041220334022
6124341003121
716066006051
oct3746564771
91327667854
10530246137
11252345853
121296b34a1
1385b15115
14505ca561
153183ee77
hex1f9ae9f9

530246137 has 2 divisors, whose sum is σ = 530246138. Its totient is φ = 530246136.

The previous prime is 530246089. The next prime is 530246141. The reversal of 530246137 is 731642035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 525143056 + 5103081 = 22916^2 + 2259^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530246137 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 530246099 and 530246108.

It is not a weakly prime, because it can be changed into another prime (530246837) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265123068 + 265123069.

It is an arithmetic number, because the mean of its divisors is an integer number (265123069).

Almost surely, 2530246137 is an apocalyptic number.

It is an amenable number.

530246137 is a deficient number, since it is larger than the sum of its proper divisors (1).

530246137 is an equidigital number, since it uses as much as digits as its factorization.

530246137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 31.

The square root of 530246137 is about 23027.0739999680. The cubic root of 530246137 is about 809.3924911810.

The spelling of 530246137 in words is "five hundred thirty million, two hundred forty-six thousand, one hundred thirty-seven".