Base | Representation |
---|---|
bin | 100110100101001010111… |
… | …1100101011001110010111 |
3 | 200202220200201022022221012 |
4 | 1031022111330223032113 |
5 | 1143334012332313020 |
6 | 15135534244042435 |
7 | 1055044011563123 |
oct | 115122574531627 |
9 | 20686621268835 |
10 | 5302505354135 |
11 | 1764864044470 |
12 | 7177b239341b |
13 | 2c6040c78332 |
14 | 1448dd530583 |
15 | 92de4d177c5 |
hex | 4d295f2b397 |
5302505354135 has 128 divisors (see below), whose sum is σ = 7818276556800. Its totient is φ = 3402279659520.
The previous prime is 5302505354063. The next prime is 5302505354161. The reversal of 5302505354135 is 5314535052035.
It is not a de Polignac number, because 5302505354135 - 210 = 5302505353111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5302505354092 and 5302505354101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 3077483384 + ... + 3077485106.
It is an arithmetic number, because the mean of its divisors is an integer number (61080285600).
Almost surely, 25302505354135 is an apocalyptic number.
5302505354135 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5302505354135 is a deficient number, since it is larger than the sum of its proper divisors (2515771202665).
5302505354135 is a wasteful number, since it uses less digits than its factorization.
5302505354135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3501.
The product of its (nonzero) digits is 675000, while the sum is 41.
The spelling of 5302505354135 in words is "five trillion, three hundred two billion, five hundred five million, three hundred fifty-four thousand, one hundred thirty-five".
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