Base | Representation |
---|---|
bin | 110001011000100010… |
… | …101110010011100001 |
3 | 12001212102002102201021 |
4 | 301120202232103201 |
5 | 1332043411330441 |
6 | 40205344005441 |
7 | 3555003646132 |
oct | 613042562341 |
9 | 161772072637 |
10 | 53025105121 |
11 | 2054032032a |
12 | a33a000881 |
13 | 5000704261 |
14 | 27d03cdc89 |
15 | 15a52473d1 |
hex | c588ae4e1 |
53025105121 has 4 divisors (see below), whose sum is σ = 53030449044. Its totient is φ = 53019761200.
The previous prime is 53025105109. The next prime is 53025105139. The reversal of 53025105121 is 12150152035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 25740672721 + 27284432400 = 160439^2 + 165180^2 .
It is a cyclic number.
It is not a de Polignac number, because 53025105121 - 221 = 53023007969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53025105521) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2657050 + ... + 2676931.
It is an arithmetic number, because the mean of its divisors is an integer number (13257612261).
Almost surely, 253025105121 is an apocalyptic number.
It is an amenable number.
53025105121 is a deficient number, since it is larger than the sum of its proper divisors (5343923).
53025105121 is an equidigital number, since it uses as much as digits as its factorization.
53025105121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5343922.
The product of its (nonzero) digits is 1500, while the sum is 25.
Adding to 53025105121 its reverse (12150152035), we get a palindrome (65175257156).
The spelling of 53025105121 in words is "fifty-three billion, twenty-five million, one hundred five thousand, one hundred twenty-one".
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