Base | Representation |
---|---|
bin | 110001011000100011… |
… | …010000001110010101 |
3 | 12001212102100111021220 |
4 | 301120203100032111 |
5 | 1332043430302203 |
6 | 40205351000553 |
7 | 3555005065155 |
oct | 613043201625 |
9 | 161772314256 |
10 | 53025244053 |
11 | 20540405751 |
12 | a33a069159 |
13 | 5000752572 |
14 | 27d0428765 |
15 | 15a5273653 |
hex | c588d0395 |
53025244053 has 4 divisors (see below), whose sum is σ = 70700325408. Its totient is φ = 35350162700.
The previous prime is 53025244043. The next prime is 53025244067. The reversal of 53025244053 is 35044252035.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53025244053 - 214 = 53025227669 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53025244043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8837540673 + ... + 8837540678.
It is an arithmetic number, because the mean of its divisors is an integer number (17675081352).
Almost surely, 253025244053 is an apocalyptic number.
It is an amenable number.
53025244053 is a deficient number, since it is larger than the sum of its proper divisors (17675081355).
53025244053 is a wasteful number, since it uses less digits than its factorization.
53025244053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17675081354.
The product of its (nonzero) digits is 72000, while the sum is 33.
Adding to 53025244053 its reverse (35044252035), we get a palindrome (88069496088).
The spelling of 53025244053 in words is "fifty-three billion, twenty-five million, two hundred forty-four thousand, fifty-three".
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