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5302535011133 = 6779142313599
BaseRepresentation
bin100110100101001011110…
…1101110011101100111101
3200202220202210010001200112
41031022113231303230331
51143334042430324013
615135541223435405
71055044521632513
oct115122755635475
920686683101615
105302535011133
111764879860188
127178002b5b65
132c6047160159
141449034504b3
1592de7724ba8
hex4d297b73b3d

5302535011133 has 4 divisors (see below), whose sum is σ = 5381677324800. Its totient is φ = 5223392697468.

The previous prime is 5302535011129. The next prime is 5302535011153. The reversal of 5302535011133 is 3311105352035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5302535011133 - 22 = 5302535011129 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5302535011133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5302535011153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39571156733 + ... + 39571156866.

It is an arithmetic number, because the mean of its divisors is an integer number (1345419331200).

Almost surely, 25302535011133 is an apocalyptic number.

It is an amenable number.

5302535011133 is a deficient number, since it is larger than the sum of its proper divisors (79142313667).

5302535011133 is an equidigital number, since it uses as much as digits as its factorization.

5302535011133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79142313666.

The product of its (nonzero) digits is 20250, while the sum is 32.

The spelling of 5302535011133 in words is "five trillion, three hundred two billion, five hundred thirty-five million, eleven thousand, one hundred thirty-three".

Divisors: 1 67 79142313599 5302535011133