Base | Representation |
---|---|
bin | 111100010010010101010000… |
… | …0110101110010001100001011 |
3 | 2120112120202121111211202021012 |
4 | 1320210222200311302030023 |
5 | 1024001142421414343312 |
6 | 5115453343111434135 |
7 | 216460556611010366 |
oct | 17044524065621413 |
9 | 2515522544752235 |
10 | 530285130621707 |
11 | 143a6872a80512a |
12 | 4b58498938594b |
13 | 199b789a18b236 |
14 | 94d3d19c070dd |
15 | 4148dee774322 |
hex | 1e24aa0d7230b |
530285130621707 has 2 divisors, whose sum is σ = 530285130621708. Its totient is φ = 530285130621706.
The previous prime is 530285130621671. The next prime is 530285130621731. The reversal of 530285130621707 is 707126031582035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 530285130621707 - 212 = 530285130617611 is a prime.
It is not a weakly prime, because it can be changed into another prime (530285130621737) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265142565310853 + 265142565310854.
It is an arithmetic number, because the mean of its divisors is an integer number (265142565310854).
Almost surely, 2530285130621707 is an apocalyptic number.
530285130621707 is a deficient number, since it is larger than the sum of its proper divisors (1).
530285130621707 is an equidigital number, since it uses as much as digits as its factorization.
530285130621707 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2116800, while the sum is 50.
The spelling of 530285130621707 in words is "five hundred thirty trillion, two hundred eighty-five billion, one hundred thirty million, six hundred twenty-one thousand, seven hundred seven".
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