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5302853641777 is a prime number
BaseRepresentation
bin100110100101010101010…
…1101010010011000110001
3200202221120222200011202111
41031022222231102120301
51143340221013014102
615140033005045321
71055055441146026
oct115125255223061
920687528604674
105302853641777
111764a226aa09a
1271788ab56841
132c6098181cb3
141449338b354d
1592e156b3cd7
hex4d2aab52631

5302853641777 has 2 divisors, whose sum is σ = 5302853641778. Its totient is φ = 5302853641776.

The previous prime is 5302853641769. The next prime is 5302853641783. The reversal of 5302853641777 is 7771463582035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3636988453921 + 1665865187856 = 1907089^2 + 1290684^2 .

It is a cyclic number.

It is not a de Polignac number, because 5302853641777 - 23 = 5302853641769 is a prime.

It is a super-2 number, since 2×53028536417772 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5302853641727) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651426820888 + 2651426820889.

It is an arithmetic number, because the mean of its divisors is an integer number (2651426820889).

Almost surely, 25302853641777 is an apocalyptic number.

It is an amenable number.

5302853641777 is a deficient number, since it is larger than the sum of its proper divisors (1).

5302853641777 is an equidigital number, since it uses as much as digits as its factorization.

5302853641777 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 29635200, while the sum is 58.

The spelling of 5302853641777 in words is "five trillion, three hundred two billion, eight hundred fifty-three million, six hundred forty-one thousand, seven hundred seventy-seven".