Base | Representation |
---|---|
bin | 110001011000110101… |
… | …011001101000110011 |
3 | 12001212202022011212122 |
4 | 301120311121220303 |
5 | 1332101140014303 |
6 | 40210040544455 |
7 | 3555063400334 |
oct | 613065315063 |
9 | 161782264778 |
10 | 53030001203 |
11 | 20543064883 |
12 | a33b78212b |
13 | 500172994a |
14 | 27d0d0628b |
15 | 15a58b2e38 |
hex | c58d59a33 |
53030001203 has 2 divisors, whose sum is σ = 53030001204. Its totient is φ = 53030001202.
The previous prime is 53030001187. The next prime is 53030001209. The reversal of 53030001203 is 30210003035.
53030001203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53030001203 - 24 = 53030001187 is a prime.
It is not a weakly prime, because it can be changed into another prime (53030001209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26515000601 + 26515000602.
It is an arithmetic number, because the mean of its divisors is an integer number (26515000602).
Almost surely, 253030001203 is an apocalyptic number.
53030001203 is a deficient number, since it is larger than the sum of its proper divisors (1).
53030001203 is an equidigital number, since it uses as much as digits as its factorization.
53030001203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270, while the sum is 17.
Adding to 53030001203 its reverse (30210003035), we get a palindrome (83240004238).
The spelling of 53030001203 in words is "fifty-three billion, thirty million, one thousand, two hundred three".
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