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5303003003041 is a prime number
BaseRepresentation
bin100110100101011001110…
…0111000011100010100001
3200202221222101201111220011
41031022303213003202201
51143341022232044131
615140055502244521
71055062233535432
oct115126347034241
920687871644804
105303003003041
111764a99a45457
12717910b86741
132c60c00b9243
14144949673489
1592e238690b1
hex4d2b39c38a1

5303003003041 has 2 divisors, whose sum is σ = 5303003003042. Its totient is φ = 5303003003040.

The previous prime is 5303003002963. The next prime is 5303003003059. The reversal of 5303003003041 is 1403003003035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4484166232225 + 818836770816 = 2117585^2 + 904896^2 .

It is a cyclic number.

It is not a de Polignac number, because 5303003003041 - 221 = 5303000905889 is a prime.

It is not a weakly prime, because it can be changed into another prime (5303003003071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651501501520 + 2651501501521.

It is an arithmetic number, because the mean of its divisors is an integer number (2651501501521).

Almost surely, 25303003003041 is an apocalyptic number.

It is an amenable number.

5303003003041 is a deficient number, since it is larger than the sum of its proper divisors (1).

5303003003041 is an equidigital number, since it uses as much as digits as its factorization.

5303003003041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 22.

Adding to 5303003003041 its reverse (1403003003035), we get a palindrome (6706006006076).

The spelling of 5303003003041 in words is "five trillion, three hundred three billion, three million, three thousand, forty-one".