Base | Representation |
---|---|
bin | 1111011011110000111… |
… | …11011111111001000101 |
3 | 1212200210200201020011221 |
4 | 13231320133133321011 |
5 | 32142024420003141 |
6 | 1043341223000341 |
7 | 53212250610541 |
oct | 7557037377105 |
9 | 1780720636157 |
10 | 530302500421 |
11 | 194999a33581 |
12 | 869392990b1 |
13 | 3b0130a7ab5 |
14 | 1b9498d2a21 |
15 | dbdb0b1bd1 |
hex | 7b787dfe45 |
530302500421 has 4 divisors (see below), whose sum is σ = 530358811200. Its totient is φ = 530246189644.
The previous prime is 530302500391. The next prime is 530302500467. The reversal of 530302500421 is 124005203035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 530302500421 - 25 = 530302500389 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530302500821) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28141261 + ... + 28160098.
It is an arithmetic number, because the mean of its divisors is an integer number (132589702800).
Almost surely, 2530302500421 is an apocalyptic number.
It is an amenable number.
530302500421 is a deficient number, since it is larger than the sum of its proper divisors (56310779).
530302500421 is an equidigital number, since it uses as much as digits as its factorization.
530302500421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56310778.
The product of its (nonzero) digits is 3600, while the sum is 25.
Adding to 530302500421 its reverse (124005203035), we get a palindrome (654307703456).
The spelling of 530302500421 in words is "five hundred thirty billion, three hundred two million, five hundred thousand, four hundred twenty-one".
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