Base | Representation |
---|---|
bin | 100110100101011010100… |
… | …1111001011111101010111 |
3 | 200202222001022002100222021 |
4 | 1031022311033023331113 |
5 | 1143341101224104003 |
6 | 15140102315314011 |
7 | 1055063014550035 |
oct | 115126517137527 |
9 | 20688038070867 |
10 | 5303030300503 |
11 | 176500339a441 |
12 | 71791a14b907 |
13 | 2c60c59560a0 |
14 | 14494d13b555 |
15 | 92e25e5c2bd |
hex | 4d2b53cbf57 |
5303030300503 has 4 divisors (see below), whose sum is σ = 5710955708248. Its totient is φ = 4895104892760.
The previous prime is 5303030300419. The next prime is 5303030300521. The reversal of 5303030300503 is 3050030303035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5303030300503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5303030300903) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203962703853 + ... + 203962703878.
It is an arithmetic number, because the mean of its divisors is an integer number (1427738927062).
Almost surely, 25303030300503 is an apocalyptic number.
5303030300503 is a deficient number, since it is larger than the sum of its proper divisors (407925407745).
5303030300503 is a wasteful number, since it uses less digits than its factorization.
5303030300503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 407925407744.
The product of its (nonzero) digits is 6075, while the sum is 25.
Adding to 5303030300503 its reverse (3050030303035), we get a palindrome (8353060603538).
The spelling of 5303030300503 in words is "five trillion, three hundred three billion, thirty million, three hundred thousand, five hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •