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5303030300503 = 13407925407731
BaseRepresentation
bin100110100101011010100…
…1111001011111101010111
3200202222001022002100222021
41031022311033023331113
51143341101224104003
615140102315314011
71055063014550035
oct115126517137527
920688038070867
105303030300503
11176500339a441
1271791a14b907
132c60c59560a0
1414494d13b555
1592e25e5c2bd
hex4d2b53cbf57

5303030300503 has 4 divisors (see below), whose sum is σ = 5710955708248. Its totient is φ = 4895104892760.

The previous prime is 5303030300419. The next prime is 5303030300521. The reversal of 5303030300503 is 3050030303035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5303030300503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5303030300903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203962703853 + ... + 203962703878.

It is an arithmetic number, because the mean of its divisors is an integer number (1427738927062).

Almost surely, 25303030300503 is an apocalyptic number.

5303030300503 is a deficient number, since it is larger than the sum of its proper divisors (407925407745).

5303030300503 is a wasteful number, since it uses less digits than its factorization.

5303030300503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 407925407744.

The product of its (nonzero) digits is 6075, while the sum is 25.

Adding to 5303030300503 its reverse (3050030303035), we get a palindrome (8353060603538).

The spelling of 5303030300503 in words is "five trillion, three hundred three billion, thirty million, three hundred thousand, five hundred three".

Divisors: 1 13 407925407731 5303030300503