Base | Representation |
---|---|
bin | 1111011011110001111… |
… | …00111010111100011101 |
3 | 1212200211020020002102000 |
4 | 13231320330322330131 |
5 | 32142033403312110 |
6 | 1043342100152513 |
7 | 53212403303430 |
oct | 7557074727435 |
9 | 1780736202360 |
10 | 530310213405 |
11 | 1949a3321445 |
12 | 8693b998739 |
13 | 3b0148786ab |
14 | 1b94a93d817 |
15 | dbdbad71c0 |
hex | 7b78f3af1d |
530310213405 has 64 divisors (see below), whose sum is σ = 1077623377920. Its totient is φ = 242389793088.
The previous prime is 530310213403. The next prime is 530310213413. The reversal of 530310213405 is 504312013035.
530310213405 is a `hidden beast` number, since 5 + 3 + 0 + 310 + 2 + 1 + 340 + 5 = 666.
It is not a de Polignac number, because 530310213405 - 21 = 530310213403 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530310213403) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6558754 + ... + 6639116.
It is an arithmetic number, because the mean of its divisors is an integer number (16837865280).
Almost surely, 2530310213405 is an apocalyptic number.
It is an amenable number.
530310213405 is an abundant number, since it is smaller than the sum of its proper divisors (547313164515).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530310213405 is a wasteful number, since it uses less digits than its factorization.
530310213405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87367 (or 87361 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
The spelling of 530310213405 in words is "five hundred thirty billion, three hundred ten million, two hundred thirteen thousand, four hundred five".
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