Base | Representation |
---|---|
bin | 110001011000111110… |
… | …101101101011110011 |
3 | 12001212220220012212011 |
4 | 301120332231223303 |
5 | 1332102301130421 |
6 | 40210205143351 |
7 | 3555123216211 |
oct | 613076555363 |
9 | 161786805764 |
10 | 53032442611 |
11 | 20544482075 |
12 | a34055ab57 |
13 | 50020a2c75 |
14 | 27d137dcb1 |
15 | 15a5be64e1 |
hex | c58fadaf3 |
53032442611 has 2 divisors, whose sum is σ = 53032442612. Its totient is φ = 53032442610.
The previous prime is 53032442513. The next prime is 53032442677. The reversal of 53032442611 is 11624423035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53032442611 - 217 = 53032311539 is a prime.
It is not a weakly prime, because it can be changed into another prime (53032448611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26516221305 + 26516221306.
It is an arithmetic number, because the mean of its divisors is an integer number (26516221306).
Almost surely, 253032442611 is an apocalyptic number.
53032442611 is a deficient number, since it is larger than the sum of its proper divisors (1).
53032442611 is an equidigital number, since it uses as much as digits as its factorization.
53032442611 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 53032442611 its reverse (11624423035), we get a palindrome (64656865646).
The spelling of 53032442611 in words is "fifty-three billion, thirty-two million, four hundred forty-two thousand, six hundred eleven".
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