Base | Representation |
---|---|
bin | 100110100101100011000… |
… | …0110000100011101001111 |
3 | 200202222210000021020201011 |
4 | 1031023012012010131033 |
5 | 1143342141124420101 |
6 | 15140150341230051 |
7 | 1055103020524621 |
oct | 115130606043517 |
9 | 20688700236634 |
10 | 5303313123151 |
11 | 176513900126a |
12 | 717998a02327 |
13 | 2c613c41b474 |
14 | 14497891cc11 |
15 | 92e40bc6751 |
hex | 4d2c618474f |
5303313123151 has 4 divisors (see below), whose sum is σ = 5303499671232. Its totient is φ = 5303126575072.
The previous prime is 5303313123149. The next prime is 5303313123161. The reversal of 5303313123151 is 1513213133035.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5303313123151 - 21 = 5303313123149 is a prime.
It is a super-2 number, since 2×53033131231512 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5303313123131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93231391 + ... + 93288256.
It is an arithmetic number, because the mean of its divisors is an integer number (1325874917808).
Almost surely, 25303313123151 is an apocalyptic number.
5303313123151 is a deficient number, since it is larger than the sum of its proper divisors (186548081).
5303313123151 is a wasteful number, since it uses less digits than its factorization.
5303313123151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 186548080.
The product of its (nonzero) digits is 12150, while the sum is 31.
Adding to 5303313123151 its reverse (1513213133035), we get a palindrome (6816526256186).
The spelling of 5303313123151 in words is "five trillion, three hundred three billion, three hundred thirteen million, one hundred twenty-three thousand, one hundred fifty-one".
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