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530334410104391 = 836389571206077
BaseRepresentation
bin111100010010101100001101…
…0001000000101111001000111
32120112202110210212212211221112
41320211120122020011321013
51024002444332441320031
65115532133054035235
7216464253033466514
oct17045303210057107
92515673725784845
10530334410104391
11143a87618794922
124b592440aa8b1b
13199bc421886b49
1494d647297c30b
15414a335c4262b
hex1e2561a205e47

530334410104391 has 4 divisors (see below), whose sum is σ = 536723981310552. Its totient is φ = 523944838898232.

The previous prime is 530334410104351. The next prime is 530334410104441. The reversal of 530334410104391 is 193401014433035.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530334410104391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530334410104321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3194785602956 + ... + 3194785603121.

It is an arithmetic number, because the mean of its divisors is an integer number (134180995327638).

Almost surely, 2530334410104391 is an apocalyptic number.

530334410104391 is a deficient number, since it is larger than the sum of its proper divisors (6389571206161).

530334410104391 is an equidigital number, since it uses as much as digits as its factorization.

530334410104391 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6389571206160.

The product of its (nonzero) digits is 233280, while the sum is 41.

The spelling of 530334410104391 in words is "five hundred thirty trillion, three hundred thirty-four billion, four hundred ten million, one hundred four thousand, three hundred ninety-one".

Divisors: 1 83 6389571206077 530334410104391