Base | Representation |
---|---|
bin | 111100010010101100001101… |
… | …0001000000101111001110001 |
3 | 2120112202110210212212212000002 |
4 | 1320211120122020011321301 |
5 | 1024002444332441320213 |
6 | 5115532133054035345 |
7 | 216464253033466604 |
oct | 17045303210057161 |
9 | 2515673725785002 |
10 | 530334410104433 |
11 | 143a87618794960 |
12 | 4b592440aa8b55 |
13 | 199bc421886b7c |
14 | 94d647297c33b |
15 | 414a335c42658 |
hex | 1e2561a205e71 |
530334410104433 has 32 divisors (see below), whose sum is σ = 634251809295360. Its totient is φ = 437735110901760.
The previous prime is 530334410104351. The next prime is 530334410104441. The reversal of 530334410104433 is 334401014433035.
It is a cyclic number.
It is not a de Polignac number, because 530334410104433 - 216 = 530334410038897 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530334410104493) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 36155585 + ... + 48661022.
It is an arithmetic number, because the mean of its divisors is an integer number (19820369040480).
Almost surely, 2530334410104433 is an apocalyptic number.
It is an amenable number.
530334410104433 is a deficient number, since it is larger than the sum of its proper divisors (103917399190927).
530334410104433 is a wasteful number, since it uses less digits than its factorization.
530334410104433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84817817.
The product of its (nonzero) digits is 311040, while the sum is 38.
Adding to 530334410104433 its reverse (334401014433035), we get a palindrome (864735424537468).
The spelling of 530334410104433 in words is "five hundred thirty trillion, three hundred thirty-four billion, four hundred ten million, one hundred four thousand, four hundred thirty-three".
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