Base | Representation |
---|---|
bin | 11000000111011111100001… |
… | …11111101011111010101111 |
3 | 20221210000000221202120221020 |
4 | 30003233300333223322233 |
5 | 23422402120113234021 |
6 | 304443252453505223 |
7 | 14112403032522456 |
oct | 1403576077537257 |
9 | 227700027676836 |
10 | 53034004430511 |
11 | 1599765a9a87a5 |
12 | 5b46418942213 |
13 | 237911512b180 |
14 | d14c066d3b9d |
15 | 61e80982a7c6 |
hex | 303bf0febeaf |
53034004430511 has 32 divisors (see below), whose sum is σ = 77295176985600. Its totient is φ = 32146207150464.
The previous prime is 53034004430507. The next prime is 53034004430587. The reversal of 53034004430511 is 11503440043035.
It is not a de Polignac number, because 53034004430511 - 22 = 53034004430507 is a prime.
It is a super-2 number, since 2×530340044305112 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53034004430611) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27278061 + ... + 29157513.
It is an arithmetic number, because the mean of its divisors is an integer number (2415474280800).
Almost surely, 253034004430511 is an apocalyptic number.
53034004430511 is a deficient number, since it is larger than the sum of its proper divisors (24261172555089).
53034004430511 is a wasteful number, since it uses less digits than its factorization.
53034004430511 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1890335.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 53034004430511 its reverse (11503440043035), we get a palindrome (64537444473546).
The spelling of 53034004430511 in words is "fifty-three trillion, thirty-four billion, four million, four hundred thirty thousand, five hundred eleven".
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